Model 4 Train Vs Pole/Signal Post/Man Practice Questions Answers Test with Solutions & More Shortcuts

Question : 21 [SSC CGL Tier-II 2014]

A train 300 m long is running with a speed of 54 km/hr. In what time will it cross a telephone pole?

a) 15 seconds

b) 17 seconds

c) 18 seconds

d) 20 seconds

Answer: (d)

Using Rule 1,

Speed of train = 54 kmph

= $({54 × 5}/18)$ m/sec = 15 m/sec

Required time = $\text"Length of trains"/ \text"Speedof train"$

= $300/15$ = 20 seconds

Question : 22 [SSC CGL Prelim 2005]

If a train, with a speed of 60 km/ hr, crosses a pole in 30 seconds, the length of the train (in metres) is :

a) 900

b) 750

c) 500

d) 1000

Answer: (c)

Using Rule 1,

Speed of train = 60 kmph

= 60 × $5/18 = 50/3$ m/sec

Length of train = Speed × Time

= $50/3 × 30$ = 500 m

Question : 23 [SSC CHSL 2015]

A train is 250m long. If the train takes 50 seconds to cross a tree by the railway line, then the speed of the train in km/hr is :

a) 9

b) 5

c) 18

d) 10

Answer: (c)

Using Rule 1,

Speed of train = $\text"Length of train"/ \text"Time taken in crossing"$

= $250/50$ = 5 m/sec.

= $(5 × 18/5)$ kmph = 18 kmph

Question : 24 [SSC CGL Prelim 2000]

How many seconds will a 500 metre long train take to cross a man walking with a speed of 3 km/hr. in the direction of the moving train if the speed of the train is 63 km/hr ?

a) 30 sec

b) 40 sec

c) 45 sec

d) 25 sec

Answer: (a)

Using Rule 5,

Relative speed of train

= 63–3 = 60 kmph

= $60 × 5/18$ m / sec

Time = $\text"Length of train"/ \text"Relative Speed"$

= ${500 × 18}/{60 × 5}$ = 30 sec.

Question : 25 [SSC CGL Prelim 1999]

A train 100m long is running at the speed of 30 km/hr. The time (in second) in which it will pass a man standing near the railway line is :

a) 11

b) 12

c) 15

d) 10

Answer: (b)

Using Rule 1, 

If a train crosses an electric pole, a sitting/standing man, km or milestone etc. then distance = Length of the train.
Then, Length of train = Speed × Time And Time = $\text"Length of train"/\text"Speed"$
and Speed = $\text"Length of train"/\text"Time"$

In this situation, the train covers it length.

Required time = $100/{30 × 1000}$ hr.

= ${100 × 60 × 60}/{30 × 1000}$ = 12 seconds

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